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x^2-296x+2304=0
a = 1; b = -296; c = +2304;
Δ = b2-4ac
Δ = -2962-4·1·2304
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{78400}=280$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-296)-280}{2*1}=\frac{16}{2} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-296)+280}{2*1}=\frac{576}{2} =288 $
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